Optimal. Leaf size=196 \[ -\frac{3 b \left (8 a^2+12 a b+5 b^2\right ) \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (c+d x)}{\sqrt{a}}\right )}{8 a^{7/2} d (a+b)^{5/2}}-\frac{(2 a+3 b) (4 a+5 b) \cot (c+d x)}{8 a^3 d (a+b)^2}+\frac{b \cot (c+d x) \left ((4 a+b) \tan ^2(c+d x)+4 a+5 b\right )}{8 a^2 d (a+b)^2 \left ((a+b) \tan ^2(c+d x)+a\right )}+\frac{b \csc (c+d x) \sec ^3(c+d x)}{4 a d (a+b) \left ((a+b) \tan ^2(c+d x)+a\right )^2} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.254987, antiderivative size = 196, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.217, Rules used = {3187, 468, 577, 453, 205} \[ -\frac{3 b \left (8 a^2+12 a b+5 b^2\right ) \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (c+d x)}{\sqrt{a}}\right )}{8 a^{7/2} d (a+b)^{5/2}}-\frac{(2 a+3 b) (4 a+5 b) \cot (c+d x)}{8 a^3 d (a+b)^2}+\frac{b \cot (c+d x) \left ((4 a+b) \tan ^2(c+d x)+4 a+5 b\right )}{8 a^2 d (a+b)^2 \left ((a+b) \tan ^2(c+d x)+a\right )}+\frac{b \csc (c+d x) \sec ^3(c+d x)}{4 a d (a+b) \left ((a+b) \tan ^2(c+d x)+a\right )^2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 3187
Rule 468
Rule 577
Rule 453
Rule 205
Rubi steps
\begin{align*} \int \frac{\csc ^2(c+d x)}{\left (a+b \sin ^2(c+d x)\right )^3} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (1+x^2\right )^3}{x^2 \left (a+(a+b) x^2\right )^3} \, dx,x,\tan (c+d x)\right )}{d}\\ &=\frac{b \csc (c+d x) \sec ^3(c+d x)}{4 a (a+b) d \left (a+(a+b) \tan ^2(c+d x)\right )^2}-\frac{\operatorname{Subst}\left (\int \frac{\left (1+x^2\right ) \left (-4 a-5 b+(-4 a-b) x^2\right )}{x^2 \left (a+(a+b) x^2\right )^2} \, dx,x,\tan (c+d x)\right )}{4 a (a+b) d}\\ &=\frac{b \csc (c+d x) \sec ^3(c+d x)}{4 a (a+b) d \left (a+(a+b) \tan ^2(c+d x)\right )^2}+\frac{b \cot (c+d x) \left (4 a+5 b+(4 a+b) \tan ^2(c+d x)\right )}{8 a^2 (a+b)^2 d \left (a+(a+b) \tan ^2(c+d x)\right )}+\frac{\operatorname{Subst}\left (\int \frac{(2 a+3 b) (4 a+5 b)+(2 a+b) (4 a+b) x^2}{x^2 \left (a+(a+b) x^2\right )} \, dx,x,\tan (c+d x)\right )}{8 a^2 (a+b)^2 d}\\ &=-\frac{(2 a+3 b) (4 a+5 b) \cot (c+d x)}{8 a^3 (a+b)^2 d}+\frac{b \csc (c+d x) \sec ^3(c+d x)}{4 a (a+b) d \left (a+(a+b) \tan ^2(c+d x)\right )^2}+\frac{b \cot (c+d x) \left (4 a+5 b+(4 a+b) \tan ^2(c+d x)\right )}{8 a^2 (a+b)^2 d \left (a+(a+b) \tan ^2(c+d x)\right )}-\frac{\left (3 b \left (8 a^2+12 a b+5 b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+(a+b) x^2} \, dx,x,\tan (c+d x)\right )}{8 a^3 (a+b)^2 d}\\ &=-\frac{3 b \left (8 a^2+12 a b+5 b^2\right ) \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (c+d x)}{\sqrt{a}}\right )}{8 a^{7/2} (a+b)^{5/2} d}-\frac{(2 a+3 b) (4 a+5 b) \cot (c+d x)}{8 a^3 (a+b)^2 d}+\frac{b \csc (c+d x) \sec ^3(c+d x)}{4 a (a+b) d \left (a+(a+b) \tan ^2(c+d x)\right )^2}+\frac{b \cot (c+d x) \left (4 a+5 b+(4 a+b) \tan ^2(c+d x)\right )}{8 a^2 (a+b)^2 d \left (a+(a+b) \tan ^2(c+d x)\right )}\\ \end{align*}
Mathematica [A] time = 1.70502, size = 214, normalized size = 1.09 \[ \frac{\csc ^6(c+d x) (-2 a+b \cos (2 (c+d x))-b) \left (\frac{4 a^{3/2} b^2 \sin (2 (c+d x))}{a+b}+\frac{3 b \left (8 a^2+12 a b+5 b^2\right ) (2 a-b \cos (2 (c+d x))+b)^2 \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (c+d x)}{\sqrt{a}}\right )}{(a+b)^{5/2}}+\frac{\sqrt{a} b^2 (10 a+7 b) \sin (2 (c+d x)) (2 a-b \cos (2 (c+d x))+b)}{(a+b)^2}+8 \sqrt{a} \cot (c+d x) (2 a-b \cos (2 (c+d x))+b)^2\right )}{64 a^{7/2} d \left (a \csc ^2(c+d x)+b\right )^3} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.13, size = 367, normalized size = 1.9 \begin{align*} -{\frac{3\,{b}^{2} \left ( \tan \left ( dx+c \right ) \right ) ^{3}}{2\,d \left ( a \left ( \tan \left ( dx+c \right ) \right ) ^{2}+ \left ( \tan \left ( dx+c \right ) \right ) ^{2}b+a \right ) ^{2}{a}^{2} \left ( a+b \right ) }}-{\frac{7\,{b}^{3} \left ( \tan \left ( dx+c \right ) \right ) ^{3}}{8\,d{a}^{3} \left ( a \left ( \tan \left ( dx+c \right ) \right ) ^{2}+ \left ( \tan \left ( dx+c \right ) \right ) ^{2}b+a \right ) ^{2} \left ( a+b \right ) }}-{\frac{3\,{b}^{2}\tan \left ( dx+c \right ) }{2\,d \left ( a \left ( \tan \left ( dx+c \right ) \right ) ^{2}+ \left ( \tan \left ( dx+c \right ) \right ) ^{2}b+a \right ) ^{2}a \left ({a}^{2}+2\,ab+{b}^{2} \right ) }}-{\frac{9\,{b}^{3}\tan \left ( dx+c \right ) }{8\,d \left ( a \left ( \tan \left ( dx+c \right ) \right ) ^{2}+ \left ( \tan \left ( dx+c \right ) \right ) ^{2}b+a \right ) ^{2}{a}^{2} \left ({a}^{2}+2\,ab+{b}^{2} \right ) }}-3\,{\frac{b}{d \left ({a}^{2}+2\,ab+{b}^{2} \right ) a\sqrt{a \left ( a+b \right ) }}\arctan \left ({\frac{ \left ( a+b \right ) \tan \left ( dx+c \right ) }{\sqrt{a \left ( a+b \right ) }}} \right ) }-{\frac{9\,{b}^{2}}{2\,{a}^{2}d \left ({a}^{2}+2\,ab+{b}^{2} \right ) }\arctan \left ({ \left ( a+b \right ) \tan \left ( dx+c \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}}-{\frac{15\,{b}^{3}}{8\,d{a}^{3} \left ({a}^{2}+2\,ab+{b}^{2} \right ) }\arctan \left ({ \left ( a+b \right ) \tan \left ( dx+c \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}}-{\frac{1}{d{a}^{3}\tan \left ( dx+c \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] time = 2.24403, size = 2275, normalized size = 11.61 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.18756, size = 313, normalized size = 1.6 \begin{align*} -\frac{\frac{3 \,{\left (8 \, a^{2} b + 12 \, a b^{2} + 5 \, b^{3}\right )}{\left (\pi \left \lfloor \frac{d x + c}{\pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (2 \, a + 2 \, b\right ) + \arctan \left (\frac{a \tan \left (d x + c\right ) + b \tan \left (d x + c\right )}{\sqrt{a^{2} + a b}}\right )\right )}}{{\left (a^{5} + 2 \, a^{4} b + a^{3} b^{2}\right )} \sqrt{a^{2} + a b}} + \frac{12 \, a^{2} b^{2} \tan \left (d x + c\right )^{3} + 19 \, a b^{3} \tan \left (d x + c\right )^{3} + 7 \, b^{4} \tan \left (d x + c\right )^{3} + 12 \, a^{2} b^{2} \tan \left (d x + c\right ) + 9 \, a b^{3} \tan \left (d x + c\right )}{{\left (a^{5} + 2 \, a^{4} b + a^{3} b^{2}\right )}{\left (a \tan \left (d x + c\right )^{2} + b \tan \left (d x + c\right )^{2} + a\right )}^{2}} + \frac{8}{a^{3} \tan \left (d x + c\right )}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]